Answer:

1). MOLE fraction of sugar in syrup = 1/101

2). Molality of sugar in syrup = 0.5 mol/ kg

>> NOTE : MOLARITY CAN'T BE CALCULATED WITH GIVEN MASS, IT IS ONLY CALCULATED WITH VOLUME, BUT MOLALITY CAN BE CALCULATED.

Explanation:

1). Mole fraction :

>>no. of moles of sugar(SOLUTE)/total moles of solution(solution)

(1). sugar = C12H22011

Weight of sugar = 34.2g (given)

Molar mass of sugar = 342 g/mol

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>> mole of sugar = 34.2/342 = 1/10 mole

(II). Water = H2O

Weight of water = 214.2-34.2=180 g Molar mass of water = 18 g/mol

>> mole of water = 180/18 = 10 mole

Now,

>> Mole fraction = (1/10)/(101/10)

= 1/10 × 10/101

[Answer] = 1/101 [ Mole fraction

is a unit less quantity]

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2). Molality

>> If mass is given in gram then,

Molality (weight of solute × 1000)/ = (Molar mass of solute × weight of solvent)

Hence,

weight of solute (Sugar) = 34.2 g (Given)

weight of solvent (water) = 180 g (Given)

Molar mass of solute = = 342 g

» (34.2 x 1000)/(342 × 180)

= 34200/61560

= 0.5 mole/Kg [Answer]