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34.95 mole of phosphorus vapour weighs 0.0625gat 0.1 bar pressure. What is the molar mass of phosphorus ? |
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Answer» Solution :ACCORDING to ideal gas equation. `Pv= nRT` Now, `n=(W)/(M):. Pv=(WRT)/(M) or M=(WRT)/(PV)` Substituting the values of from data `M=(0*0625gxx0*83 "BAR" L K^(-1) "mol"^(-1) xx819*15K)/(1"bar" xx34*04xx10^(-3)L)` `:. M=124*8 g "mol"^(-1)` |
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