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34. For the cell reaction : 2Cu(aCu)Cuu(agi thestandard cell potential is 0.36 V. The equilibriumconstant for the reaction is12.

Answer»

E° = (0.059/n)log(Kc)

here n = no. of electrons exchanged , so n = 2

and E° is 0.36v

now, 0.36 = (0.059/2)log(Kc)=> log(Kc) = 0.36*2/0.059 = 12.20

so, Kc = 10^(12+0.2) = 10^0.2 × 10¹² = 1.58×10¹²


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