1.

`34 g` of `H_(2)O_(2)` is present in `1120 ml` of `H_(2)O` solution. This solution is called.A. `10 vol` solutionB. `20 vol` solutionC. `34 vol` solutionD. `32 vol` solution

Answer» Correct Answer - A
`N=(W_(2)xx1000)/(EW_(2)xxVmL)`
`=(34xx1000)/(17xx1120)=200/12`
`1 N of H_(2)O_(2)=5.6 ` vol strength
`200/12 N of H_(2)O_(2)=5.6xx200/12=10` vol strength


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