InterviewSolution
Saved Bookmarks
| 1. |
`34 g` of `H_(2)O_(2)` is present in `1120 ml` of `H_(2)O` solution. This solution is called.A. `10 vol` solutionB. `20 vol` solutionC. `34 vol` solutionD. `32 vol` solution |
|
Answer» Correct Answer - A `N=(W_(2)xx1000)/(EW_(2)xxVmL)` `=(34xx1000)/(17xx1120)=200/12` `1 N of H_(2)O_(2)=5.6 ` vol strength `200/12 N of H_(2)O_(2)=5.6xx200/12=10` vol strength |
|