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34.The seventh term of an Arithmetic progressionprogression is four times its secondterm and twelfth term is 2 more than three times of its fourthan three times of its fourth term. Findthe progression. |
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Answer» a7 = 4 × a2 a + 6d = 4 × (a + d) a + 6d = 4a + 4d 6d - 4d = 4a - a 2d = 3a -> ( 1 ) a12 = 2 + 3 × (a4) a + 11d = 2 + 3 × (a + 3d) a + 11d = 2 + 3a + 9d 11d - 9d = 2 + 3a - a 2d = 2 + 2a From eq. ( 1 ) 3a = 2 + 2a 3a - 2a = 2 a = 2-> ( 2 ) Putting value of eq. ( 2 ) in eq. ( 1 ) 2d = 3a2d = 3(2) 2d = 6 d = 6/2 = 3 Hence, the A.P. is a, a+d, a+2d, a+3d..............a+(n-1)d 2, 5, 8, 11..............so on. |
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