35.4 mL of HCl is required for the neutralization of a solution containing 0.275 g of sodium hydroxide. The normality of hydrochloric acid isA. 0.97 NB. 0.142 NC. 0.194 ND. 0.244 N

35.4 mL of HCl is required for the neutralization of a solution contai

1.	35.4 mL of HCl is required for the neutralization of a solution containing 0.275 g of sodium hydroxide. The normality of hydrochloric acid isA. 0.97 NB. 0.142 NC. 0.194 ND. 0.244 N
Answer» Correct Answer - C We know that 1 g equivalent weight of NaOH = 40 g `therefore` 40 g of NaOH = 1 g eq. of NaOH `therefore 0.275 g` of `NaOH =(1)/(40xx0.275 eq.` `=(1)/(40)xx0.275xx1000=6.88` meq. `therefore underset((HCl))(N_(1)V_(1))=underset((NaOH))(N_(2)V_(2))` `N_(1)xx35.4=6.88 " " (because meq = NV)` `N_(1)=0.194`.

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35.4 mL of HCl is required for the neutralization of a solution containing 0.275 g of sodium hydroxide. The normality of hydrochloric acid isA. 0.97 NB. 0.142 NC. 0.194 ND. 0.244 N

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