1.

35 ml of oxygen were collected at 6°C and 758 mm pressure. Calculate its volume at NTP.

Answer»
Given conditionsFinal conditions
V1 = 35 ml
P1 = 758 mm
T1 = 6+273
= 279 K		V2 = ?
P2 = 760 mm
T2 = 0 + 273
= 273 K

By applying ideal gas equation, we have

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

\(\frac{758\times35}{279}\) = \(\frac{760\times V_2}{273}\)

\(\therefore\) V2 = \(\frac{758\times35}{279}\) x \(\frac{273}{760}\)

= 34∙16 ml

Volume of chlorine gas at NIP = 34∙16 ml.


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