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36 A student connects 10 dry cells each of emf \( E \) and internal resistance \( r \) in series, but by mistake the one cell gets wrongly connected. Then net emf and net internal resistance of the combination will be\( \begin{array}{ll}\text { a } & 8 E , 8 r \\ \text { b } & 10 E , 10 r \\ \text { c } & 8 E , 10 r \\ \text { d } & 8 E , r / 10\end{array} \) |
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Answer» Option c 8E , 10r ● Total emf = 9E - E = 8E ( minus due to polarity change) ● Internal resistance does not depend on polarity so R = 10r
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