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37. The energy of a photon is 3x10-12 ergs. Whatis its wavelength in nm ?(h=6.62 x 10-27 erg. sec; C=3x1010Cm.s-1)

Answer»

Using Planck's formula,E=hc/wwhere w is the wavelength,3*10^(-12) = 6.62*10^(-27) * 3*10^10 / ww = 6.62*10^(-5) cm = 662 nm.

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662nm is the right answer

by E=HC/W622nm answer

622nm is the correct answer of this problem

622nm is the correct answer



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