38. A diagonal of a parallelogram divides it into two congruent triang

1.	38. A diagonal of a parallelogram divides it into two congruent triangles.
Answer» Given:- A parallelogram ABCD and AC is its diagonal . To prove :- △ABC≅△CDA Proof :- In△ABC and△CDA,we have ∠DAC =∠BCA [alt. int. angles, since AD\| \| BC] AC = AC [common side] And ∠BAC=∠DAC[alt. int. angles,since AB\| \| DC] ∴ By ASA congruence axiom, we have △ABC≅△CDA Hope it helps you

38. A diagonal of a parallelogram divides it into two congruent triangles.

Answer»

Given:-

A parallelogram ABCD and AC is its diagonal .

To prove :-

△ABC≅△CDA

Proof :-

In△ABC and△CDA,we have

∠DAC =∠BCA [alt. int. angles, since AD| | BC]

AC = AC [common side]

And

∠BAC=∠DAC[alt. int. angles,since AB| | DC]

∴ By ASA congruence axiom, we have

△ABC≅△CDA

Hope it helps you