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39.A bullet of mass 20 g is fired horizontally with a velocity of 150m/s from a pistol of mass 2kg. What is the recoil velocity of the pistol? |
| Answer» <html><body><p>the <a href="https://interviewquestions.tuteehub.com/tag/recoil-1180224" style="font-weight:bold;" target="_blank" title="Click to know more about RECOIL">RECOIL</a> velocity of the pistol is 1.5 m/s.Explanation:Mass of <a href="https://interviewquestions.tuteehub.com/tag/bullet-403823" style="font-weight:bold;" target="_blank" title="Click to know more about BULLET">BULLET</a>, m1 = 20g (= 0.02 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>)Mass of pistol, m2 = 2 kg Initial velocity of the bullet (u1) and pistol (u2) = 0 Final velocity of the bullet, v1 = +<a href="https://interviewquestions.tuteehub.com/tag/150m-275831" style="font-weight:bold;" target="_blank" title="Click to know more about 150M">150M</a> s-1 <a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> v be the recoil velocity of the pistol. The total momentum of the pistol and bullet is zero before the fire. (Since both are at rest) Total momentum of the pistol and bullet after it is fired is = (0.02 kg x 150 m s-1) + (2 kg x v m s-1) = (3 + 2v) kg m s-1 Total momentum after the fire = Total momentum before the fire 3 + 2v = 0 →v = -1.5 m/s Thus, the recoil velocity of the pistol is 1.5 m/s. Have a great day pls mark it as brainiest ans.</p></body></html> | |