1.

39. P can completeof a work in10 days, g can complete 40% ofthe same work in 15 days, R,completes of the work in 13days and S. of the work in 736days. Who will be able to complete the work first?

Answer»

Given that P can do 1/4 of work in 10 days10 days = 1/4 of the work1 day = 1/4 ÷ 10 = 1/40 of the workP can do whole work in 40 days

Given Q can do 40% of the work in 15 days15 days = 40/100 of the work1 day = 40/100 ÷ 15 = 2/75 of the work Q can do whole work in 37.5 days

Given that R can do 1/3 of the work in 13 days13 days = 1/3 of the work1 day = 1/3 ÷ 13 = 1/39 of the workR can complete whole work in 39 days

Given that S can do 1/6 of the work in 7 days7 days = 1/6 of the work1 day = 1/6 ÷ 7 = 1/42 of the workS can complete whole work in 42 days

Therefore, Q will complete the work first



Discussion

No Comment Found