1.

3a−[4a−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯3a−5b−3{2a−(3a−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯2a−3b)}] =

Answer» 3a[4a¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯3a5b3{2a(3a¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯2a3b)}] =


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