1.

`3cos^(-1)x=cos^(-1)(4x^(3)-3x),x""in[(1)/(2),1]`

Answer» माना `cos^(-1)x=theta`
`impliesx=costheta`
`R.H.S=cos^(-1)(4x^(3)-3x)`
`=cos^(-1)(4cos^(3)theta-3costheta)`
`=cos^(-1)(cos3theta)`
`=3theta=3cos^(-1)x=L.H.S`


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