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`3cos^(-1)x=cos^(-1)(4x^(3)-3x),x""in[(1)/(2),1]` |
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Answer» माना `cos^(-1)x=theta` `impliesx=costheta` `R.H.S=cos^(-1)(4x^(3)-3x)` `=cos^(-1)(4cos^(3)theta-3costheta)` `=cos^(-1)(cos3theta)` `=3theta=3cos^(-1)x=L.H.S` |
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