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3in the adjoining figure, PQ 16 cm and 00Find the length of OM and the ar AOPO)10 cm |
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Answer» OM=6cm and at(OPQ)=48cm if pq is 16 thenom is bisector of seg pq so, pm=qm2pm=pqpm=8by p.g.t(16)square+(om)square=(10)square256+om=100(om)square=100-256 156 under root 39*4 2 root 39 OM = square root(100 - 64) = 6 cmAr(OPQ) = (1/2)(16)(6) = 48 sq.cm height of OM=4 cm and area is=32cmsq. |
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