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`3KClO_(3)+3H_(2)SO_(4)rarr3KHSO_(4)+HClO_(4)+2ClO_(2)+H_(2)O` Equivalent weight of `KClO_(3)` isA. `(M)/(4)`B. `(M)/(2)`C. `(M+(M)/(2))`D. `((M)/(4)+(M)/(2))` |
Answer» Correct Answer - C Disproportionation reaction `ClO_(3)^(ө)rarrClO_(4)^(ө)+2e^(-)(x=2)` (oxidation) `x-6= -1, x-8= -1` `x=5 , x=7` `e^(-)+ClO_(3)^(ө)rarrClO_(2), (x=1)` (reduction) `x=5, x= -4= 0` `x=4` `Ew=M+(M)/(2)` |
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