We know that any positive integer is of the form 3q or 3q + 1 or 3q + 2 for some integer q & one and only one of these possibilities can occur

Case I : When n = 3q

In this case, we have,n=3q, which is divisible by 3n=3q= adding 2 on both sidesn + 2 = 3q + 2n + 2 leaves a remainder 2 when divided by 3Therefore, n + 2 is not divisible by 3n = 3qn + 4 = 3q + 4 = 3(q + 1) + 1n + 4 leaves a remainder 1 when divided by 3n + 4 is not divisible by 3Thus, n is divisible by 3 but n + 2 and n + 4 are not divisible by 3

Case II : When n = 3q + 1

In this case, we haven = 3q +1n leaves a reaminder 1 when divided by 3n is not divisible by 3n = 3q + 1n + 2 = (3q + 1) + 2 = 3(q + 1)n + 2 is divisible by 3n = 3q + 1n + 4 = 3q + 1 + 4 = 3q + 5 = 3(q + 1) + 2n + 4 leaves a remainder 2 when divided by 3n + 4 is not divisible by 3Thus, n + 2 is divisible by 3 but n and n + 4 are not divisible by 3

Case III : When n = 3q + 2

In this case, we haven = 3q + 2n leaves remainder 2 when divided by 3n is not divisible by 3n = 3q + 2n + 2 = 3q + 2 + 2 = 3(q + 1) + 1n + 2 leaves remainder 1 when divided by 3n + 2 is not divsible by 3n = 3q + 2n + 4 = 3q + 2 + 4 = 3(q + 2)n + 4 is divisible by 3Thus, n + 4 is divisible by 3 but n and n + 2 are not divisible by 3 .

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