1.

3N H_(3)PO_(4) aqu. solutionis given = .......... gm/litre.

Answer»

98
298
33
95

Solution :Equivalent weight `=("MOLECULAR mass")/("BASICITY")= (98)/(3)`
`N=("gm/lit")/("equ.wt.")= 3 XX (98)/(3) = 98`


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