(3q+7p2-2r3+4) – (4p2-2q+7r3-3) =?(a) (p2+2q+5r3+1) (b) (11p2+q+5r3

1.	(3q+7p2-2r3+4) – (4p2-2q+7r3-3) =?(a) (p2+2q+5r3+1) (b) (11p2+q+5r3+1) (c) (-3p2-5q+9r3-7) (d) (3p2+5q-9r3+7)
Answer» (d) (3p²+5q-9r³+7) Explanation: Given (3q+7p²-2r³+4) – (4p²-2q+7r³-3) According to the rules of subtraction of algebraic equations, we have negative sign will Becomes positive and so we have to keep the big numerical sign. Now arrange the variables in rows we get (3q+7p²-2r³+4) – (4p²-2q+7r³-3) = (3p²+5q-9r³+7)

(3q+7p2-2r3+4) – (4p2-2q+7r3-3) =?(a) (p2+2q+5r3+1) (b) (11p2+q+5r3+1) (c) (-3p2-5q+9r3-7) (d) (3p2+5q-9r3+7)

Answer»

(d) (3p²+5q-9r³+7)

Explanation:

Given (3q+7p²-2r³+4) – (4p²-2q+7r³-3)

According to the rules of subtraction of algebraic equations, we have negative sign will

Becomes positive and so we have to keep the big numerical sign.

Now arrange the variables in rows we get

(3q+7p²-2r³+4) – (4p²-2q+7r³-3) = (3p²+5q-9r³+7)