InterviewSolution
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`3sin^(-1)x=sin^(-1)(3x-4x^(3)),x"in[-(1)/(2),(1)/(2)]` |
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Answer» माना `sin^(-1)x=theta` `impliesx=sintheta` `R.H.S=sin^(-1)(3x-4x^(3))` `=sin^(-1)(3sintheta-4sin^(3)theta)` `=sin^(-1)(sin3theta)` `=3theta=3sin^(-1)x` =L.H.S |
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