1.

`3sin^(-1)x=sin^(-1)(3x-4x^(3)),x"in[-(1)/(2),(1)/(2)]`

Answer» माना `sin^(-1)x=theta`
`impliesx=sintheta`
`R.H.S=sin^(-1)(3x-4x^(3))`
`=sin^(-1)(3sintheta-4sin^(3)theta)`
`=sin^(-1)(sin3theta)`
`=3theta=3sin^(-1)x`
=L.H.S


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