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3V poteniometer used for the determination of internal resistance of a 2.4V cell. The balanced point of the cell in open circuit is 75.8cm. When a resistor of `10.2Omega` is used in the external circuit of the cell the balance point shifts to 68.3cm length of the potentiometer wire. The internal resistance of the cell is A. `2.5Omega`B. `2.25Omega`C. `1.12Omega`D. `3.2Omega`

Answer» Correct Answer - C
Internal resistance of cell
`r=R((l_(1))/(l_(2))-1)=1.5xx(65)/(32)=3.05V`
`l_(2)=68.3cm or r=10.2((75.8)/(68.3)-1)=1.12Omega`


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