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3When K2Cr2O7 is converted into K Croa, the change in oxidation number of Cris(D) 3lato(C) 4(B) 6 |
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Answer» A is the answer of the following When is converted into then the change in oxidation number of chromium is zero. In case of K has charge +1.Cr has charge x.O has charge -2.The charge on this whole molecule is 0. Therefore, the oxidation number of Cr is calculated as follows. 2 + 2x - 14 = 0 x = 6 In case of K has charge +1.Cr has charge x.O has charge -2.The charge on this whole molecule is 0. Therefore, the oxidation number of Cr is calculated as follows. 2 + x - 8 = 0 x = 6 Thus, it can be concluded that there is no change in the oxidation state of Chromium . the answer of the following question is option (a) B is because O. N of o is -2 and k is 1, so let cr be x and 2 + x+(-2×4)=+6 option a is the correct answer of this question (a) is the right answer of following questions option b is the correct answer of the given question option (a) is the right answer. option A is the right answer |
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