3x2-64. Find the perimeter of the rectangle whose dimensions are zerov

1.	3x2-64. Find the perimeter of the rectangle whose dimensions are zerovalues of quadratic polynomial x2-7x+ 12.
Answer» Let first find the zeroes of x² -7x + 12 x² - 7x + 12 = 0 x² -3x - 4x + 12 = 0 x(x - 3) - 4 ( x - 3) = 0 (x - 3) ( x - 4) = 0 Zeroes are 3 and 4 So, perimeter is 2 × ( L + B) 2 × ( 3 + 4) = 2 × 7 = 14 units

3x2-64. Find the perimeter of the rectangle whose dimensions are zerovalues of quadratic polynomial x2-7x+ 12.

Answer»

Let first find the zeroes of x² -7x + 12

x² - 7x + 12 = 0

x² -3x - 4x + 12 = 0

x(x - 3) - 4 ( x - 3) = 0

(x - 3) ( x - 4) = 0

Zeroes are 3 and 4

So, perimeter is 2 × ( L + B)

2 × ( 3 + 4) = 2 × 7 = 14 units