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4 = 0 has equal rootsardelsj Ork, if the quadratic equation3X2-KV3X17. Find the eleventh term from the last term of the AP: 27, 23, 19... -65.18. The sum of firrt nt |
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Answer» 27 , 23 , 19 ,...., - 65 is an A.P a = 27 , common difference = a2 - a1 d = 23 - 27 = - 4 Rewrite the A..P , - 65 , - 61 , - 57 , ... 19 , 23 , 27 here , first term = a = - 65 common difference = a2 - a1 d = - 61 - ( - 65 ) d = -61 + 65 d = 4 n = 11 nth term = an = a + ( n - 1 )d a11 = -65 + ( 11 - 1 ) 4 = -65 + ( 10 × 4 ) = -65 + 40 = -25 Therefore , required 11th term = a11 = - 25 I hope this helps you. |
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