1.

4 = 0 has equal rootsardelsj Ork, if the quadratic equation3X2-KV3X17. Find the eleventh term from the last term of the AP: 27, 23, 19... -65.18. The sum of firrt nt

Answer»

27 , 23 , 19 ,...., - 65 is an A.P

a = 27 ,

common difference = a2 - a1

d = 23 - 27 = - 4

Rewrite the A..P ,

- 65 , - 61 , - 57 , ... 19 , 23 , 27

here ,

first term = a = - 65

common difference = a2 - a1

d = - 61 - ( - 65 )

d = -61 + 65

d = 4

n = 11

nth term = an = a + ( n - 1 )d

a11 = -65 + ( 11 - 1 ) 4

= -65 + ( 10 × 4 )

= -65 + 40

= -25

Therefore ,

required 11th term = a11 = - 25

I hope this helps you.



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