1.

4.0g of argon ( at. Mass = 40) in a bulb at a temperature of T K has a pressure P atm. When the bulb was placed in a hotter bath at a temperature 50^(@)C more than the first one, 0.8g of gas had to be removed to get the original temperature T which is equal to

Answer»

<P>510K
200K
100K
73 K

Solution :Moles of ARGON `= ( 4)/( 40) =0.1`
Now, `p V = nRT`
or `PV = 0.1 RT `
In hot bath, n `= ( 4.0 - 0.8)/( 40) = 0.08`
`:. pV = 0.08 R ( T + 50)`
`:. 0.1 RT = 0.08 R ( T + 50)`
or `T = 200K`


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