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`4*48` litre of methane at S.T.P. correspods toA. `1*2xx10^(22)` molecules of methaneB. `0*5` mole of methaneC. `3*2` g of methaneD. `0*1` mole of methane |
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Answer» Correct Answer - C `4*48` litre `CH_(4)=(4*48)/(22*4) = (1)/(5) = 0.2` mol `=16xx0*2=3*2gCH_(4)` `=0*2xx6*02xx10^(22)` molecules. |
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