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`4.9 g` of `K_(2)Cr_(2)O_(7)` is taken to prepare `0.1 L` of the solutio. `10 mL` of this solution is further taken to oxidise `Sn^(2+)` ion into `Sn^(4+) ion` so produced is used in second reaction to prepare `Fe^(3+)` ion then the millimoles of `Fe^(3+)` ion formed will be (assume all other components are in sufficient amount)[Molar mass of `K_(2)Cr_(2)O_(7)=294 g`].A. 5B. 20C. 10D. 15 |
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Answer» Correct Answer - C N of `K_(2)Cr_(2)O_(7) = (4.9 xx 1)/(49xx 0.1) = 1N` No. of m.equts orf `Fe^(+3) =` No. of m.eqts of `Sn^(4+)` =No. of m.equts of `K_(2)Cr_(2)O_(7) = 10 xx 1 = 10` |
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