1.

4.9 gm/lit of H_(2)SO_(4) is given ........... Is normality

Answer»

0.2
20
10
0.1

Solution :`H_(2)SO_(4)` equivalent weight `=(98)/(2) = 49 gm/"equt"^(-1)`
`N=("gm/litre")/("equivalent")=(4.9)/(49)=0.1`


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