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4 A room is 4.8 m long, 3.6 m broad and 2 m high. Find the cost oflaying tiles on its floor and its four walls at the rate of? 100/ m |
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Answer» Dimensions of the room : Length ( l ) = 4.8 m , Breadth ( b ) = 3.6 m, Height ( h ) = 2 m i ) Area of the floor ( A1 ) = lb = 4.8 m × 3.6 m = 17.28 m² ---( 1 ) ii ) Area of four walls of the room ( A2 ) = 2( l + b )h = 2( 4.8 + 3.6 )× 2 = 2 × 8.4 × 2 = 33.6 m² ----( 2 ) iii ) Total area of laying tiles = A1 + A2 = 17.28 m² + 33.6 m² = 50.88 m² It is given that cost of tiles for 1m² = Rs 100 Cost laying tiles 50.88m² area = 100 × 50.88 = Rs 5088 |
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