1.

4 A room is 4.8 m long, 3.6 m broad and 2 m high. Find the cost oflaying tiles on its floor and its four walls at the rate of? 100/ m

Answer»

Dimensions of the room :

Length ( l ) = 4.8 m ,

Breadth ( b ) = 3.6 m,

Height ( h ) = 2 m

i ) Area of the floor ( A1 ) = lb

= 4.8 m × 3.6 m

= 17.28 m² ---( 1 )

ii ) Area of four walls of the room ( A2 )

= 2( l + b )h

= 2( 4.8 + 3.6 )× 2

= 2 × 8.4 × 2

= 33.6 m² ----( 2 )

iii ) Total area of laying tiles = A1 + A2

= 17.28 m² + 33.6 m²

= 50.88 m²

It is given that cost of tiles

for 1m² = Rs 100

Cost laying tiles 50.88m² area

= 100 × 50.88

= Rs 5088



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