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4. A verandah of width 2.25 m is constructed all along outside a room which is 5.5mlong and 4 m wide. Find:(1) the area of the verandah.(i) the cost of cementing the floor of the verandah at the rate of 7200 per m.5. A path 1 m wide is built along the border and inside ou |
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Answer» (i)The length of room = 5.5 m and width of the room = 4 m The length of room with verandah = 5.5 + 2.25 + 2.25 = 10 m The width of room with verandah = 4 + 2.25 + 2.25 = 8.5 m Area of verandah = Area of room with verandah – Area of room without verandah = Area of ABCD – Area of EFGH = (AB x AD) – (EF x EH) = (10 x 8.5) – (5.5 x 4) = 85 – 22 = 63 m2 (ii) The cost of cementing 1 m2 the floor of verandah = Rs200 The cost of cementing 63 m2 the floor of verandah = 200 x 63 = Rs12,600 |
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