4. An oxygen tank contained 219L of oxygen before 32-L were used. If t

1.	4. An oxygen tank contained 219L of oxygen before 32-L were used. If the tank can hold 245much space in the tank is unused?L, how
Answer» Oxygen in tank initially = 219 2/3 L Oxygen in tank left = 219 2/3 - 32 1/3= 659/3 - 97/3= 562/3 Total capacity of tank = 245 3/8 L Therefore, unused space in tank = 245 3/8 - 562/3= 1963/8 - 562/3= (5889 - 4496)/24= 1393/24= 58 1/24 L tanks

4. An oxygen tank contained 219L of oxygen before 32-L were used. If the tank can hold 245much space in the tank is unused?L, how

Answer»

Oxygen in tank initially = 219 2/3 L

Oxygen in tank left = 219 2/3 - 32 1/3= 659/3 - 97/3= 562/3

Total capacity of tank = 245 3/8 L

Therefore, unused space in tank = 245 3/8 - 562/3= 1963/8 - 562/3= (5889 - 4496)/24= 1393/24= 58 1/24 L

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