4.How many terms of the AP. 18,16,14,be taken so that their sum is zer

1.	4.How many terms of the AP. 18,16,14,be taken so that their sum is zero? (n=
Answer» Sn=0a=18d=16-18=-2n=?Sn=n/2 (2a+(n-1)d)0=n/2 (36+(n-1)(-2))36-2n+2=038-2n=038=2nn=19 A.T.QGivenSn=0T1=a1=18d=16-18 =-2n=?then, we know thatSn=n/2[2a+(n-1)d]0=n/2[2(18)+(n-1)(-2)]0=n[36-2n+2]0=n[38-2n]0/n=38-2n0=38-2n38=2nn=38/2 =19 Ans

4.How many terms of the AP. 18,16,14,be taken so that their sum is zero? (n=

Answer»

Sn=0a=18d=16-18=-2n=?Sn=n/2 (2a+(n-1)d)0=n/2 (36+(n-1)(-2))36-2n+2=038-2n=038=2nn=19

A.T.QGivenSn=0T1=a1=18d=16-18 =-2n=?then, we know thatSn=n/2[2a+(n-1)d]0=n/2[2(18)+(n-1)(-2)]0=n[36-2n+2]0=n[38-2n]0/n=38-2n0=38-2n38=2nn=38/2 =19 Ans

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4.How many terms of the AP. 18,16,14,be taken so that their sum is zero? (n=

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