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`4` identical balls of radius `R` and mass `m` are lying a gravity free space. The balls are in contact and there centres are forming vertices of a square of side `2R` in horizontal plane. One identical ball travelling vertically with a speed `v` hits the four balls symmetrically. The collision is perfectly elastic. The centre of the `4` stationery ball are at (`R`, `R`, `0`), (`R`, `-R`, `0`) and (`-R`, `-R`,`0`) initially. The speed of ball `1` after collision is : A. `(sqrt(2))/(3)v`B. `(v)/(sqrt(2))`C. `(6)/(11)sqrt((2)/(3))`D. none of these |
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Answer» `mv=(4mv_(1))/(sqrt(2))+mv_(2)`……(`1`) `1=(v_(1)=(v_(2))/(sqrt(2)))/(v//sqrt(2))`.....(`2`) `v_(1)=(sqrt(2)v)/(3)` |
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