4 If05 mol of BaCl2 is mixed with 0.2 mol of Nas POs, the maximum numb

1.	4 If05 mol of BaCl2 is mixed with 0.2 mol of Nas POs, the maximum number of moles of Bas(POsh that can beformed is0.7B) 0.5C) 0.300.10
Answer» Firstly Write Balanced Chemical Equation In these questions. 6BaCl2 + 4Na3PO4 ==>2Ba3(PO4)2 + 12NaCl In these Question You Need To find Limiting Reagent. Now See Balance Equation For Every 6 moles of BaCl2 4 Moles of Na3PO4 are required For every 1 mole of BaCl2 4/6 moles of Na3PO4 required. For 0.5 moles of BaCl2=(4/6)×0.5=0.3333 moles of Na3PO4 are required. But we have Only 0.2 moles Of Na3PO4 are given,so it is limiting reagent. Now Coming to the question, 4 Moles of Na3PO4 will give out 2 moles of Na3(PO4)2 1 mole of Na3PO4=2/4 moles of Na3(PO4)2 0.2 moles of Na3PO4=1/2×0.2=0.1

4 If05 mol of BaCl2 is mixed with 0.2 mol of Nas POs, the maximum number of moles of Bas(POsh that can beformed is0.7B) 0.5C) 0.300.10

Answer»

Firstly Write Balanced Chemical Equation In these questions.

6BaCl2 + 4Na3PO4 ==>2Ba3(PO4)2 + 12NaCl

In these Question You Need To find Limiting Reagent.

Now See Balance Equation

For Every 6 moles of BaCl2 4 Moles of Na3PO4 are required

For every 1 mole of BaCl2 4/6 moles of Na3PO4 required.

For 0.5 moles of BaCl2=(4/6)×0.5=0.3333 moles of Na3PO4 are required.

But we have Only 0.2 moles Of Na3PO4 are given,so it is limiting reagent.

Now Coming to the question,

4 Moles of Na3PO4 will give out 2 moles of Na3(PO4)2

1 mole of Na3PO4=2/4 moles of Na3(PO4)2

0.2 moles of Na3PO4=1/2×0.2=0.1