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4. In ∆PQR, ∠P = 70°, ∠Q = 65°, then find ∠R.​

Answer»

<P>angle R = 45°

Explanation:

we KNOW that sum of angles of TRIANGLE is 180°

angle P + angle Q + angle R = 180°

70°+65°+angle R = 180°

135° + angle R = 180°

angle R = 180°- 135°

angle R = 45°

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