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4 kg of ice at `-20^(@)C` is mixed with 5 kg of water at `40^(@)C`. The water content in the equilibrium mixture is `(S_("water")=1kcal//kg-C,S_(ice)=0.5kcal//kg-c,L_(f(water))=80kcal//kg)`A. 6 kgB. 7 kgC. 8 kgD. 9 kg |
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Answer» Correct Answer - B Equilibrium temperature of mixutre is `0^(@)C` Total heat released by water `=m_(W)s_(W)Deltatheta=5xx1xx40=200kcal` Heat taken by ice to increase its temperature from `-20^(@)C` to `0^(@)C=4xx0.5xx20=40kcal` `therefore` mass of ice melted `=(200-40)/(80)=(160)/(80)=2kg` `therefore` water content in the equilibrium mixture `=5+2=7kg` |
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