4 litre of water are added to 2litre of 6 molar HCL solution .what is

1.	4 litre of water are added to 2litre of 6 molar HCL solution .what is the molarity of resulying solution?
Answer» Explanation: The number of MOLES of HCl ORIGINALLY present does not change. Only the concentration of the solutions change . original moles of SOLUTION,n1 = final moles of solution,n2- - -1 molarity(M)=no. of moles of solute/ vol of solution in litre therefore n1=Vol 1M1- - -2 n2 =Vol 2M2- - -3 on equating 1,2&3 we get, Vol1M1 = Vol2M2 Vol1 = 2 liters M1 = 6 M Vol2 = 6 liters ( original 2 + 4 liters added) M2 = ? ( 2 L )(6M)=( 6 L) (?) on solving we get, M2 =final molarity = (2L x 6M)/6L = 2 M

4 litre of water are added to 2litre of 6 molar HCL solution .what is the molarity of resulying solution?

Answer»

Explanation:

The number of MOLES of HCl ORIGINALLY present does not change. Only the concentration of the solutions change .

original moles of SOLUTION,n1 = final moles of solution,n2- - -1

molarity(M)=no. of moles of solute/ vol of solution in litre

therefore

n1=Vol 1*M1- - -2

n2 =Vol 2*M2- - -3

on equating 1,2&3 we get,

Vol1M1 = Vol2M2

Vol1 = 2 liters

M1 = 6 M

Vol2 = 6 liters ( original 2 + 4 liters added)

M2 = ?

( 2 L )(6M)=( 6 L) (?)

on solving we get,

M2 =final molarity = (2L x 6M)/6L = 2 M