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4 MARKS QUESTIONS1. In △ABC, seg MMN ll side AC. Seg MN dividesAABC into two parts equal in area. DetermineAMMB(HOTS)

Answer»

in ΔABC and ΔAMN

segment MN ║ BC

∠AMN=∠ABC (corresponding angle)

∠ANM=∠ACB (corresponding angle)

∠A si common

so ΔABC≅ΔAMN (CPCT)

given that 2*(area of ΔAMN )= area of ΔABC

so

AM/MB =√(ar(ABC)/ar(AMN))

= √2/1

= √2

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