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4 MARKS QUESTIONS1. In âłABC, seg MMN ll side AC. Seg MN dividesAABC into two parts equal in area. DetermineAMMB(HOTS) |
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Answer» in ΔABC and ΔAMN segment MN ║ BC ∠AMN=∠ABC (corresponding angle) ∠ANM=∠ACB (corresponding angle) ∠A si common so ΔABC≅ΔAMN (CPCT) given that 2*(area of ΔAMN )= area of ΔABC so AM/MB =√(ar(ABC)/ar(AMN)) = √2/1 = √2 Like my answer if you find it useful! |
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