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4 men or 6 women or 15 children can complete a work in 15 days. Find out the time taken by 2 men, 4 women and 5 children together to complete twice the initial amount of work.1. 102. 153. 204. 25 |
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Answer» Correct Answer - Option 3 : 20 Given : 4 men or 6 women or 15 children can complete a work in 15 days Concept used : working efficiency per day × Total days taken by the person = Total work Calculations : Let the total work be 'W' Let the working efficiency of man, woman and children will be 'm' , 'w' and 'c' respectively According to the question 4 m × 15 = 6 w × 15 = 15 c × 15 = W So, W = 60 m = 90 w = 225 c Let time taken by 2 men, 4 women and 5 children be 't' days (2 m + 4 w + 5 c) × t = 2 W (3 w + 4 w + 2w ) × t = 2 × (90 w) (4 m = 6 w or 2 m = 3 w, 15 c = 6 w or 5 c = 2 w and W = 90 w) 9 w × t = 180 w t = 20 days ∴ 2 men, 4 women and 5 children will take 20 days together to complete the whole work
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