InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
4 ^ { \operatorname { log } _ { 2 } \operatorname { log } x } = \operatorname { log } x - ( \operatorname { log } x ) ^ { 2 } + 1 |
|
Answer» 4^log(2)logx = logx -(logx)²+1 here 4 = 2² so 2^2log(2)logx = logx -(logx)²+1 => (logx)² = logx -(logx)² +1 assume logx = t => t² = t-t²+1 => 2t²-t-1 = 0 => 2t²-2t+t-1 = 0 => 2t(t-1)+1(t-1) =0 => (t-1)(2t-1) = 0 so, t = 1 , t = 1/2. the value of logx = 1, 1/2 or x = e or √e. |
|