4-Pentenoic acid when treated with I_(2) and NaHCO_(3) gives:

1.	4-Pentenoic acid when treated with I_(2) and NaHCO_(3) gives:
Answer» <html><body><p>4,5-diiodopentanoic acid<br/>5-iodomethyl-dihydrofuran-2-one<br/>5-<a href="https://interviewquestions.tuteehub.com/tag/iodo-2747950" style="font-weight:bold;" target="_blank" title="Click to know more about IODO">IODO</a>-tetrahydropyran-2-one<br/>4-pentenolyiodide</p>Solution :Iodo lactonization.</body></html>

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