4-Pentenoic acid when treated with I_(2) and NaHCO_(3) gives:

1.	4-Pentenoic acid when treated with I_(2) and NaHCO_(3) gives:
Answer» 4,5-diiodopentanoic acid 5-iodomethyl-dihydrofuran-2-one 5-IODO-tetrahydropyran-2-one 4-pentenolyiodide Solution :Iodo lactonization.

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