1.

-4*sqrt(3)/(sqrt(2) %2B sqrt(6)) %2B (3*sqrt(2))/(sqrt(3) %2B sqrt(6)) %2B sqrt(6)/(sqrt(2) %2B sqrt(3))

Answer»

3V2( V3-V6)/(V3)^2+(V6)^2=3V6-3V12/3-6=-3V6/9, 4V3(V6-V2)/(V6)^2×( V2)^2=4V18-4V6/6

3V2 x V3-V6/( V3)^2-( V6)^2=3V6-3V12/3-6=-3V6/-3=3V6/3= V6____(1), 4V3(V6-V2)/( V6)^2-( V2)^2=4V18-4V6/6-2=4V12/4=- V12_________(2), V6 x(V2-V3)/(V2)^2-(V3)^2=V12-V18/2-3=-V6/-1_________(3), V6- V12-V6=V6-V12-V6=-V12

3V2/V3+V6=3V2 x (V3-V6)/( V3)^2-( V6)^2=3V6-3V12/3-6=3(V6-V12)/3=V6______(1); 4V3/V6+V2=4V3(V6-V2)/( V6)^2-(V2)^2=4V18-4V6/6-2=4(V9)/-4=-3___________(2) V6/V2+V3 × V2-V3/V2-V3= V6(V2-V3)/( V2)^2-(V3)^2= V8-V18/2-3=V10/-1=-V10__(3) V6-(-3)-V10= V16+3=4+3=7

3V6/V3+V6- 4V3/V6+V3 + V6/V2+V3 =3V2(V3-V6)/3-6 -4V3(V6-V3)6-3 + V6( V2-V3)/2-3= 3( V6-V6)/3 -4(V18-V6)/4-( V12-V18)=V6-V6-V18+ V6-V12+V18=-V6


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