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    				| 1. | 4. The amount of heat produced, on complete burning of 10 kg of a given fuelin pure oxygen, equals H kilojoule. The calorific fuel, of that fuel, would equa(10 H) kJ/kg(0.1 H) kJ/kg(H+10) kJ/kg(H-10) kJ/kgplease explain with answer. | 
| Answer» ong>Answer: We know Mass of fuel× calorific value=mass of water ×specific HEAT ×temperature difference Given mass of fuel m 
 =10 kg and mass of water m 
 = 2kg ΔT=70 0 −20 0 =50 0 C Specific heat of water =4.186J/grams 0 C=4.186×10 −3 J/kg 0 C Now putting the above values in the equation we get C V 
 = 10 2×4.186×10 −3 ×(70−20) 
 =4.186×10 −2 J/kg | |