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4.The amount of heat produced, on complete burning of 10 kg of a given fuelin pure oxygen, equals H kilojoule. The calorific fuel, of that fuel, would equa(10 H) kJ/kg(0.1 H) kJ/kg(H+10) kJ/kg(H-10) kJ/kgplease explain with answer. |
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Answer» Answer: We KNOW Mass of fuel× calorific value=mass of water ×specific heat ×temperature difference Given mass of fuel m
=10 kg and mass of water m
= 2kg ΔT=70 −20 0 =50 0 C Specific heat of water =4.186J/grams 0 C=4.186×10 −3 J/kg 0 C Now putting the above values in the equation we GET C V
= 10 2×4.186×10 −3 ×(70−20)
=4.186×10 −2 J/kg |
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