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4. यदि x = 2+ J2, तब +4 का मान है ।है

Answer»

x^2=(2+√2)^2=4+2+4√2=6+4√21/x^2=1/6+4√2*6-4√2/6-4√2=6-4√2/36-32=6-4√2/4hencex^2+4/x^26+4√2+6-4√2=12



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