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4 years hence the mother will be twice of his son, the sum of present age is 46, find present age |
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Answer» Let the present age of mother and her son be x and y years respectively.It is given that , sum of their present age is 46.=>x+y=46----------(1)Four years hence,Mother's age=x+4Son's age=y+4 It is given that 4 years hence, mother's age will be twice that of son's age.=>(x+4)=2(y+4)==>x-2y=4------------(2) eqn(1)×2=>2x+2y=92eqn(2)×1=>x - 2y=4------------------------------------------------ 3x=96=>x=32=>y=46-x=46-32=14 ∴Mother's present age=32Son's present age=14 Thnks ji |
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