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40 ml of methane is completely burnt using 80 ml of oxygen at room temperature. The volume of gas left after cooling to room temperature is

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> ml of `CO_(2)` <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a><br/>40 ml `CO_(2)` gas and 80 ml `H_(2)O` gas<br/><a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> ml of `CO_(2)` and 60 ml `H_(2)O` gas<br/>120 ml `CO_(2)` gas</p>Solution :`CH_(4(g)) + 2O_(2(g)) to CO_(2(g)) + 2H_(2)O_(l)` <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V01_C01_E01_001_S01.png" width="80%"/> <br/>Since the product was cooled to room temperature, water exists <a href="https://interviewquestions.tuteehub.com/tag/mostly-7382870" style="font-weight:bold;" target="_blank" title="Click to know more about MOSTLY">MOSTLY</a> as liquid. Hence, option (a) is correct</body></html>


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