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40 the equation of trajectory of a projectile projected with a velocity of 10m/satanangle45degreewithverticalisgivenby(g=10m/s)(a)y^2=10(x+y)(b)y^2=10(x-y)(c)x^2=10(x+y)(d)x^2=10(x-y)

Answer» 40 the equation of trajectory of a projectile projected with a velocity of 10m/satanangle45degreewithverticalisgivenby(g=10m/s)(a)y^2=10(x+y)(b)y^2=10(x-y)(c)x^2=10(x+y)(d)x^2=10(x-y)


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