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44.The ratio of mass percent of C and H of an organic compound (C_xH_yO_z) is 6:1. If one molecule of the above compound (C_xH_yO_z) contains half as much oxygen as required to burn one molecule of compound C_xH_y completely to CO_2 and H_2O. The emperical formula of the compound C_xH_yO_z is |
| Answer» 44.The ratio of mass percent of C and H of an organic compound (C_xH_yO_z) is 6:1. If one molecule of the above compound (C_xH_yO_z) contains half as much oxygen as required to burn one molecule of compound C_xH_y completely to CO_2 and H_2O. The emperical formula of the compound C_xH_yO_z is | |