1.

45. The hypotenuse of a right angled triangle is 17 cm and the difference of the other two sides is!7 cm, find the measure of the unknown sides of the triangle.

Answer»

Let other two sides of a triangle are a and b

Then,a - b = 7a = 7 + b....... (1)

Given,Hypotenuse h = 17 cm

Using pythagoras theoramh^2 = a^2 + b^2Put value of a from eq(1)(17)^2 = (7 + b)^2 + b^2289 = 49 + b^2 + 14b + b^22b^2 + 14b - 240 = 0b^2 + 7b - 120 = 0b^2 + 15b - 8b - 120 = 0b(b + 15) - 8(b + 15) = 0b = - 15, 8

Negative value not possible

So,Other two sides are a = 7 + 8= 15, b = 8


Discussion

No Comment Found

Related InterviewSolutions